Chlorobenzene conc H 2 SO 4- conc HNO 3- A i- KOH - - ii- H - B B Br 2 - H 2 O -1 equiv- C Sn - HCl - D Ac 2 O -1 equiv- E E will be-

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Byju's Answer

Standard XII

Chemistry

Reduction of Carboxylic Acids

Chlorobenzene...

Question

$Chlorobenzene conc H_{2} S O_{4}, conc H N O_{3} - -------------- \to Δ A i . K O H, Δ - ----- \to i i . H^{+} (B)$

$(B) B r_{2} / H_{2} O - ---- \to (1 equiv.) (C) S n / H C l - ---- \to (D) A c_{2} O - ---- \to (1 equiv.) (E)$

E will be:

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Solution

The correct option is B
Product A
Nitration of chlorobenzene gives p-chloronitrobenzene as the the major product.

Product B
Nucleophilic aromatic subtitution of $C l$ by $O H$ group gives p-chlorophenol.

Product C
Bromination occurs ortho to the $O H$ group since it is a activating group.

Product D
Reduction of nitro group with $S n / H C l$

Product E
N is more nucleophilic than $O$ and hence acetylation occurs at the amino group.

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Similar questions

N a_{2} C_{2} H C l - - \to (excess) N a N H_{2} - --------- \to (excess) C H_{3} I H_{2} - ------ \to P d - B a S O_{4} i . O_{3} - ------ \to i i . Z n - H_{2} O

Final product can be obtained by:

Chlorobenzene conc H_{2} S O_{4}, conc H N O_{3} - -------------- \to Δ A i . K O H, Δ - ----- \to i i . H^{+} (B)

(B) B r_{2} / H_{2} O - ---- \to (1 equiv.) (C) S n / H C l - ---- \to (D) A c_{2} O - ---- \to (1 equiv.) (E)

E will be:

A + H_{2} O \to B + H C l

B + H_{2} O \to C + H C l

Compound (A), (B) and (C) will be respectively:

I . P h - C H_{3} i . C r O_{2} C l_{2} - ------ \to i i . H^{+} / H_{2} O

I I . P h - C C l_{3} K O H - -- \to excess

I I I . P h - C H_{2} O H P C C - -- \to

I V . P h - O | | C - C l H_{2} - ------ \to P d - B a S O_{4}

V . P h - C \equiv N i . S n C l_{2} / H C l - ------- \to i i . H^{+} / H_{2} O

V I . P h - H C O / H C l - ------- \to anhyd. A l C l_{3}

V I I . P h - H C H_{3} C l - ------- \to anhyd. A l C l_{3} H^{+}, K M n O_{4} - ------ \to Δ

Consider following reactions and give the number of reactions which prooduce benzaldehyde as final major product.

Complete and balance the following equations. State the conditions wherever necessary.
(a) $C H \equiv C H + H_{2} \to$ ______ $+ H_{2} \to$ _________
(b) $C_{2} H_{4} + B r_{2} \to$ _________
(c) $C_{2} H_{4} + H C l \to$ _________
(d) $C a C_{2} + H_{2} O \to$ _________
(e) $C_{2} H_{2} + B r_{2} \to$ _________
(f) $C_{2} H_{5} O H [O] - ---- \to K_{2} C r_{2} O_{7}$ _________

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Chlorobenzeneconc H2SO4, conc HNO3−−−−−−−−−−−−−−−→ΔAi. KOH, Δ−−−−−−→ii. H+(B) (B)Br2/H2O−−−−−→(1 equiv.)(C)Sn/HCl−−−−−→(D)Ac2O−−−−−→(1 equiv.)(E) E will be:

$Chlorobenzene conc H_{2} S O_{4}, conc H N O_{3} - -------------- \to Δ A i . K O H, Δ - ----- \to i i . H^{+} (B)$

$(B) B r_{2} / H_{2} O - ---- \to (1 equiv.) (C) S n / H C l - ---- \to (D) A c_{2} O - ---- \to (1 equiv.) (E)$

E will be: