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Question

Factorise: 12xy8x+9y6

A
(3y2)(4x+3)
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B
(3y2)(4x3)
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C
(3y+2)(4x+3)
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D
(3y2)(3x+2)
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Solution

The correct option is A (3y2)(4x+3)
Given expression: 12xy8x+9y6

Taking 4x common from the first two terms and 3 common from the last two terms, we get

12xy8x+9y6=4x(3y2)+3(3y2)=(3y2)(4x+3)

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