The correct option is D (x+1x)(x+1x−2)
Given: x2+1x2+2−2x−2x
Combining the first three terms and last two terms we get, =(x2+1x2+2)−(2x+2x)
Applying the identity (a+b)2=a2+2ab+b2 we get,(x2+1x2+2)=(x+1x)2.
So, (x2+1x2+2)−(2x+2x)=(x+1x)2−2(x+1x)
Taking (x+1x) common, we get,
(x+1x)(x+1x−2)