The correct option is D (2x+4y)
Given that,
Total monthly income of the boy=(5y+9x)
Total monthly expenditure=(4x−6y)+(6x+2y)+(4y−x)+(y−2x)
Grouping and adding all the like terms,
(4x+6x−x−2x)+(−6y+2y+4y+y)=(7x+y)
Now, the total monthly savingof the boy= Total monthly income - Total monthly expenditure
=(9x+5y)−(7x+y)=(2x+4y)
So, the monthly saving of the boy is (2x+4y).