Question

$\text{Find the value for x, y for :}\frac{2}{x}+\frac{2}{3y}=\frac{1}{6},\frac{3}{x}+\frac{4}{y}=\frac{-1}{2}$

• A. 6, -4
• B. -3, -4
• C. 4, -6
• D. 2, -3

Answer 1

The correct option is A

6, -4

$\frac{2}{x}+\frac{2}{3y}=\frac{1}{6}.................\left(i\right)\frac{3}{x}+\frac{4}{y}=\frac{1}{2}.................\left(ii\right)\text{Solving both the equations we get}y=-4\text{Substituting y=-4 in equation (ii)}\frac{3}{x}+\frac{4}{-4}=-\frac{1}{2}\Rightarrow \frac{3}{x}-1=-\frac{1}{2}\Rightarrow \frac{3}{x}=-\frac{1}{2}+1\Rightarrow \frac{3}{x}=\frac{1}{2}\Rightarrow x=6\therefore x=6,y=-4$