Find the value of -24 x 2 y 2 x -3 y when- x-2 andy -3A- 1252B- 1456C- 1440D- 1550

The correct option is C 1440 24x^2y(2x 3y) = 24x^2y× 2x + 24x^2y× 3y = 48x^3y + 72x^2y^2 Substituting the value of x = 2 and y = 3, we get, 48x^3y + 72x^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Multiplication of a Binomial by a Monomial

Find the valu...

Question

$Find the value of - 24 x^{2} y (2 x - 3 y)$
$when, x = 2 and y = 3$ .

1252

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1440

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1550

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1456

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 1440
$- 24 x^{2} y (2 x - 3 y)$
$= - 24 x^{2} y \times 2 x + 24 x^{2} y \times 3 y$
$= - 48 x^{3} y + 72 x^{2} y^{2}$

Substituting the value of $x = 2$ and $y = 3$ ,
we get,

$- 48 x^{3} y + 72 x^{2} y^{2}$
$= - 48 (2)^{3} (3) + 72 (2)^{2} (3)^{2} = - 1152 + 2592 = 1440$

Suggest Corrections

Similar questions

Q. Find the value of

- 24 x^{2} y (2 x - 3 y)

when,

x = 2

and

y = 3

Q. Find the value of

\frac{d y}{d x}

θ = \frac{π}{4}

,if

x = a e^{θ} (s i n θ - c o s θ)

and

y = a e^{θ} (s i n θ + c o s θ)

Q. Find area bounded by curves

{(x, y) : y \geq x^{2} a n d y =∣ x ∣}

$Find the value of x if x if | x + 2 |$ = 3

Q. The graphs of

2 x + 3 y - 6 = 0, 4 x - 3 y - 6 = 0, x = 2, a n d y = \frac{2}{3}

intersect in:

Join BYJU'S Learning Program

Find the value of −24x2y(2x−3y) when, x=2 andy=3.

The correct option is B 1440−24x2y(2x−3y) =−24x2y×2x+24x2y×3y =−48x3y+72x2y2 Substituting the value of x=2 and y=3, we get, −48x3y+72x2y2 =−48(2)3(3)+72(2)2(3)2=−1152+2592=1440

$Find the value of - 24 x^{2} y (2 x - 3 y)$
$when, x = 2 and y = 3$ .

The correct option is B 1440
$- 24 x^{2} y (2 x - 3 y)$
$= - 24 x^{2} y \times 2 x + 24 x^{2} y \times 3 y$
$= - 48 x^{3} y + 72 x^{2} y^{2}$

Substituting the value of $x = 2$ and $y = 3$ ,
we get,

$- 48 x^{3} y + 72 x^{2} y^{2}$
$= - 48 (2)^{3} (3) + 72 (2)^{2} (3)^{2} = - 1152 + 2592 = 1440$