Given that y - -cx - d-b- where nbsp- b - 0 -amp- -a - c- - 0- then- what is the value of nbsp- x - if ax - by - c - 0-d-c-a-c-d - c-a - c-a-c-d-c-None

The correct option is B ( d c)/(a + c)Given, ax + by + c = 0, Also given, y=(cx+d)/b, substitute this in ax + by + c = 0 We get, ax + [b (cx + d)/b] + c ...

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Standard IX

Mathematics

Substitution Method

Given that y...

Question

$Given that y = \frac{(c x + d)}{b}$ ;

$where b \neq 0 & (a + c) \neq 0$ ,

$then, what is the value of x, if a x + b y + c = 0 ?$

\frac{(d + c)}{(a + c)}

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\frac{(- d - c)}{(a + c)}

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\frac{(a + c)}{(d + c)}

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None

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Solution

The correct option is B $\frac{(- d - c)}{(a + c)}$
$Given, a x + b y + c = 0,$
$Also given, y = \frac{(c x + d)}{b}, substitute this in a x + b y + c = 0$
$We get, a x + [b \frac{(c x + d)}{b}] + c = 0$
$\Rightarrow a x + c x + d + c = 0$
$(a + c) x = - d - c$
$∴ x = \frac{(- d - c)}{(a + c)}$

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Similar questions

Given that y = \frac{(c x + d)}{b}

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where b \neq 0 & (a + c) \neq 0

then, what is the value of x, if a x + b y + c = 0 ?

Q. Given that

y = \frac{(c x + d)}{b},where b \neq 0.

If a x + b y + c = 0, where (a + c) \neq 0

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then what is the value of

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Q. Given that,

y = \frac{(c x + d)}{b}

; where,

b \neq 0 & (a + c) \neq 0

,

then, what is the value of x, if

a x + b y + c = 0 ?

$G i v e n t h a t y = \frac{(c x + d)}{b}$ ;

then, what is the value of x, in $a x + b y + c = 0$

if $b \neq 0 & (a + c) \neq 0$ ,

In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

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Given that y=(cx+d)b; where b≠0 & (a+c)≠0, then, what is the value of x,if ax+by+c=0?

The correct option is B (−d−c)(a+c)Given, ax+by+c=0, Also given, y=(cx+d)b,substitute this in ax+by+c=0 We get, ax+[b(cx+d)b]+c=0 ⇒ax+cx+d+c=0 (a+c)x=−d−c ∴x=(−d−c)(a+c)

$Given that y = \frac{(c x + d)}{b}$ ;

$where b \neq 0 & (a + c) \neq 0$ ,

$then, what is the value of x, if a x + b y + c = 0 ?$

The correct option is B $\frac{(- d - c)}{(a + c)}$
$Given, a x + b y + c = 0,$
$Also given, y = \frac{(c x + d)}{b}, substitute this in a x + b y + c = 0$
$We get, a x + [b \frac{(c x + d)}{b}] + c = 0$
$\Rightarrow a x + c x + d + c = 0$
$(a + c) x = - d - c$
$∴ x = \frac{(- d - c)}{(a + c)}$