$How many persons can be accoummodated in a dining hall of dimensions (20 m \times 16 m \times 4.5 m), assuming thatg each person requires 5 cubic metres of air ?$

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Solution

Length of hall = 20 m

Breadth of hall = 16 m

Height of hall = 4.5 m

∴ Volume of hall = l × b × h = (20 × 16 × 4.5) $m^{3}$

Volume of air needed per person = 5 $m^{3}$

∴ Number of persons = (volume of the hall / volume of air needed for 1 person)

= $\frac{(20 \times 16 \times 4.5)}{5}$ = 288 persons

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How many persons can be accoummodated in a dining hall of dimensions (20 m×16 m×4.5 m),assuming thatg each person requires 5 cubic metres of air ?

Length of hall = 20 m Breadth of hall = 16 m Height of hall = 4.5 m ∴ Volume of hall = l × b × h = (20 × 16 × 4.5) m3 Volume of air needed per person = 5 m3 ∴ Number of persons = (volume of the hall / volume of air needed for 1 person) = (20×16×4.5)5 = 288 persons

$How many persons can be accoummodated in a dining hall of dimensions (20 m \times 16 m \times 4.5 m), assuming thatg each person requires 5 cubic metres of air ?$