If a -1-8- b -1-9 and c -3-7- then the value of a 3- b 3- c 3-A- -36-7B- -37-8C- -37-6D- -37-96

The correct option is D 37.96 Since, a + b + c =0 ∴ a^3 + b^3 + c^3 = 3abc = 37.96 ...

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If a =1.8, b ...

Question

$If a = 1.8, b = 1.9 and c = - 3.7, then the value of a^{3} + b^{3} + c^{3} =$

-37.96

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-37.6

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-36.7

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-37.8

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$If a = 1.8, b = 1.9 and c = - 3.7, then the value of a^{3} + b^{3} + c^{3} =$

a + b + c = 0

(a + b - c)^{3} + (b + c - a)^{3} + (c + a - b)^{3}

a + b + c = 9

(3 - a)^{3} + (3 - b)^{3} + (3 - c)^{3} - 3 (3 - a) (3 - b) (3 - c)

If $a + b + c = 0$ , then the value of $(a + b - c)^{3} + (b + c - a)^{3} + (c + a - b)^{3}$ is:

> 0

\frac{a^{3}}{b^{3}} + \frac{b^{3}}{c^{3}} + \frac{c^{3}}{a^{3}} \geq 3

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