$If f (x) = 2 x - 1, then the number of positive solution(s) of the equation | f (x) | = | f (| x | - 1) | is/are$

1

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2

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Solution

The correct option is A $1$
$| f (x) | = | 2 x - 1 | and | f (| x | - 1) | = | 2 | x | - 3 | ∴ | 2 x - 1 | = | 2 | x | - 3 | The graph of the above equation is |$

$∴ Only 1 postive solution.$

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