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Question

If x2+y2=14 and xy=3,
then find the value of
2(x+y)25(xy)2. [3 Marks]

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Solution

Given : x2+y2=14 ...(1)
xy=3 ...(2)

Using the identities,
(a+b)2=a2+2ab+b2
and (ab)2=a22ab+b2, [0.5 Mark]


2(x+y)25(xy)2

=2(x2+y2+2xy)5(x22xy+y2) [0.5 Mark]

=2x2 + 2y2 + 4xy - 5x2 + 10xy5y2
=(2x25x2)+(2y25y2)+(4xy+10xy)
=3x23y2+14xy
=3(x2+y2)+14xy [1 Mark]

(Substituting values from (1) and (2))
=(3×14)+(14×3)
=42+42
=0 [1 Mark]

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