Question

$\text{In the figure, area of}\Delta DAC=45c{m}^2,\text{then find the area of rectangle ABEF in}c{m}^2.$

• A. 90

Answer 1

The correct option is A 90
$\text{Given: Area of}\Delta DAC=45c{m}^2$

Diagonal AC divides the parallelogram ABCD into two triangles of equal area.

$\text{Area of ABCD =}2\times \text{Area of}\Delta DAC=90c{m}^2$

In ABCD and ABEF, AB is common base and both of them are lying between the same parallel lines i.e., AB and ED.

We know that, two parallelograms having same base and between the same parallels have equal areas.

$\therefore \text{Area of rectangle ABEF}\text{= Area of parallelogram ABCD}=90c{m}^2$