$In the given figure, AB = AC and OB =OC. Then, ∠ A B O : ∠ A C O = ? (a) 1 : 1 (b) 2 : 1 (c) 1 : 2 (d) none of these$

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Solution

ANSWER:
(a) 1:1
In ∆OAB and ∆OAC, we have:
AB=AC (Given)OB=OC (Given) OA =OA
Thus, ∆OAB≅OAC (SSS criterion)
i.e., ∠ABO=∠ACO
∴ ∠ABO : ∠ACO=1 : 1

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