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Question

Simply the equation y=(a+1)2+(a1)2.
For a = 4, value of y is

A
34
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B
25
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C
9
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D
16
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Solution

The correct option is A 34
Given , y=(a+1)2+(a1)2

(a+b)2=a2+b2+2ab

(a+1)2+(a1)2a2+1+2a+a2+12a

2a2+2
2(a2+1)

Substituting a = 4,

We get:2(42+1)=2(17)=34

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