$Subtract a (b - 5) from b (5 - a) .$

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Solution

Given expressions are:
$a (b - 5) . . . . . . . . (i)$
and $b (5 - a) . . . . (i i)$
Subtracting $(i)$ from $(i i)$ , we get:
$b (5 - a) - a (b - 5)$
$\Rightarrow 5 b - a b - a b + 5 a = 5 a + 5 b - 2 a b$
$\Rightarrow 5 (a + b) - 2 a b$

Hence, $b (5 - a) - a (b - 5) = 5 (a + b) - 2 a b$

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Subtract a(b−5) from b(5−a).

Given expressions are: a(b−5)........(i) and b(5−a)....(ii)Subtracting (i) from (ii), we get:b(5−a)−a(b−5)⇒5b−ab−ab+5a=5a+5b−2ab⇒5(a+b)−2abHence, b(5−a)−a(b−5)=5(a+b)−2ab

$Subtract a (b - 5) from b (5 - a) .$

Given expressions are:
$a (b - 5) . . . . . . . . (i)$
and $b (5 - a) . . . . (i i)$
Subtracting $(i)$ from $(i i)$ , we get:
$b (5 - a) - a (b - 5)$
$\Rightarrow 5 b - a b - a b + 5 a = 5 a + 5 b - 2 a b$
$\Rightarrow 5 (a + b) - 2 a b$

Hence, $b (5 - a) - a (b - 5) = 5 (a + b) - 2 a b$