Question

$\text{The approximate value of}\sqrt{51}\text{to nearest}$
$\text{tenths is}$

• A. 7.5
• B. 7.1
• C. 7.2
• D. 7.3

Answer 1

The correct option is B 7.1

$\text{We have to find value of}\sqrt{51}$

$\text{We know,}{7}^2=49and{8}^2=64$

Now, 49 < 51 < 64.

$\text{So,}\sqrt{49}<\sqrt{51}<\sqrt{64}$
$\Rightarrow 7<\sqrt{51}<8$

So, 51 is closer to 49.

∴ By trial-and-error method you get,

$7.1\times 7.1=50.4161$
$7.2\times 7.2=51.84$

$\text{So,}\sqrt{51}=7.1$