Question

$\text{The ascending arrangement of}\frac{2}{3},\frac{6}{7},\frac{13}{21}\text{is}$

Answer 1

Here, L.C.M. of the denominators (3, 7 and 21) is 21.

(i) $\frac{2}{3}=\frac{2\times 7}{3\times 7}=\frac{14}{21}$

(ii) $\frac{6}{7}=\frac{6\times 3}{7\times 3}=\frac{18}{21}$

(iii) $\frac{13}{21}$ need not be changed as the denominator is same as L.C.M.

Clearly,
$\frac{13}{21}<\frac{14}{21}<\frac{18}{21}$

So, the ascending order of the given fractions is,
$\frac{13}{21}<\frac{2}{3}<\frac{6}{7}$