$The intermediate frequency (IF) of an AM superheterodyne receiver is 450 kHz and the local oscilliator frequency (F_{L O}) of the mixer is set at the higher of the two possible values, such that f_{L O} > f_{c} always. If the carrier frequency (f_{c}) of the received signal is 650 kHz, then the carrier frequency of the corresponding image signal will be equal to_______kHz.$
1550

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Solution

The correct option is A 1550
$Given that, f_{c} = 650 k H z, I F = 450 k H z f_{L O} > f_{c} So, the carrier frequency of the corresponding image signal can be given as, f_{i} = f_{c} + 2 (I F) = 650 + 2 (450) = 1550 k H z$

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