Question

$\text{What is the maximum length of a pencil that can be placed in a rectangular box of dimensions}(8cm\times 6cm\times 5cm)?(Given\sqrt{5}=\mathrm{2.24.})\left(a\right)8cm\left(b\right)9.5cm\left(c\right)19cm\left(d\right)11.2cm$

Answer 1

ANSWER: (d) 11.2 cm
Maximum length of the pencil = diagonal of the box = $\sqrt{l^2+b^2+h^2}=\sqrt{64+36+25}=\sqrt{125}=5\sqrt{5}=5\times 2.24$ = 11.2 cm