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Byju's Answer
Standard XII
Mathematics
Sum of Binomial Coefficients with Alternate Signs
∫01 xe x dx =...
Question
∫
1
0
x
e
x
d
x
=
A
1
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B
e-1
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C
e
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D
e-2
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Solution
The correct option is
A
1
I
=
[
x
e
x
−
e
x
]
1
0
=
1
Suggest Corrections
0
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i
m
π
→
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∑
n
r
=
1
1
n
e
r
n
i
s
[AIEEE 2004]