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Question

x20x+sin x1+cos xdx= [Roorkee 1978]


A
-log 2
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B
log 2
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C
π2
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D
\N
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Solution

The correct option is C π2
x20x+sin x1+cos xdx=x20x+sin x2 cos2 x2dx
=12x20 x sec2 x2dx+x20 tanx2dx
=x tanx2π20=π2 tan π4=π2

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