$\int_{1}^{2} e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x =$

\frac{e^{2}}{2} + e

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e - \frac{e^{2}}{2}

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\frac{e^{2}}{2} - e

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Solution

The correct option is C $\frac{e^{2}}{2} - e$
$\int_{1}^{2} e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x = {[\frac{1}{x} e^{x}]}_{1}^{x} = \frac{e^{2}}{2} - e$

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