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Byju's Answer
Standard XIII
Mathematics
Property 1
∫ab √ [ x-a/b...
Question
∫
b
a
√
[
x
−
a
b
−
x
]
d
x
=
A
2
π
(
b
−
a
)
3
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B
π
(
b
+
a
)
2
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C
π
(
b
−
a
)
2
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D
π
(
b
−
a
)
3
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Solution
The correct option is
C
π
(
b
−
a
)
2
∫
b
a
√
[
x
−
a
b
−
x
]
d
x
=
∫
π
2
0
√
(
b
−
a
)
s
i
n
2
θ
(
b
−
a
)
c
o
s
2
θ
(
b
−
a
)
s
i
n
2
θ
d
θ
=
2.
(
b
−
a
)
∫
π
2
0
s
i
n
2
θ
d
θ
=
2
(
b
−
a
)
.
1
2
.
π
2
=
π
(
b
−
a
)
2
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Q.
∫
b
+
c
a
+
c
f
(
x
)
dx
is equal to