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Question

ba[xabx]dx=

A
2π(ba)3
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B
π(b+a)2
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C
π(ba)2
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D
π(ba)3
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Solution

The correct option is C π(ba)2
ba[xabx]dx=π20(ba)sin2θ(ba)cos2θ(ba)sin 2 θ dθ
=2.(ba)π20sin2 θ dθ=2(ba).12.π2=π(ba)2

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