Question

Th correct order of the stochiometrics of AgCl formed when $AgN{O}_3$ in excess is treated with the complexes: $CoC{l}_3.6N{H}_3,CoC{l}_3.5N{H}_3,CoC{l}_3.4N{H}_3$ respectively is

• A. 1AgCl, 3AgCl, 2AgCl
• B. 3AgCl, 1AgCl, 2AgCl
• C. 3AgCl, 2AgCl, 1AgCl
• D. 2AgCl, 3AgCl, 1AgCl

Answer 1

The correct option is C

3AgCl, 2AgCl, 1AgCl

According to Werner's theory,
$CoC{l}_3.6N{H}_3\to \left[Co\right(N{H}_3{)}_6{]}^{3+}3C{l}^{-}CoC{l}_3.5N{H}_3\to \left[Co\right(N{H}_3{)}_{5}Cl{]}^{2+}2C{l}^{-}CoC{l}_3.4N{H}_3\to \left[Co\right(N{H}_3{)}_{4}C{l}_2{]}^{+}C{l}^{-}$
When $AgN{O}_3$ in excess is treated with these complexes then following reactions takes place:
$\left[Co\right(N{H}_3{)}_6{]}^{3+}3C{l}^{-}+AgN{O}_3\to 3AgCl+\left[Co\right(N{H}_3{)}_6{]}^{3+}\left[Co\right(N{H}_3{)}_{5}Cl{]}^{2+}2C{l}^{-}+AgN{O}_3\to 2AgCl+\left[Co\right(N{H}_3{)}_{5}Cl{]}^{2+}\left[Co\right(N{H}_3{)}_{4}C{l}_2{]}^{+}C{l}^{-}+AgN{O}_3\to AgCl+\left[Co\right(N{H}_3{)}_{4}C{l}_2{]}^{+}$