Question

Th net resistance of two resistors when connected in series is 4.5 $\Omega$ and 1 $\Omega$ in parallel. The value of resistors are $\Omega$.

• A. 3 and 6
• B. 1.5 and 3
• C. 1.5 and 0.5

Answer 1

The correct option is B 1.5 and 3

For series combination, $R_{eq}$= $R_1$ + $R_2$

4.5 = $R_1$ + $R_2$

For parallel combination, $R_{eq}=\frac{R_1{R}_2}{R_1+R_2}$

1 = $\frac{R_1{R}_2}{4.5}$

$R_1$= $\frac{4.5}{R_2}$

Substituting and solving we get,

$R_1$= 1.5 $\Omega$, $R_2$= 3 $\Omega$