Question

that the child has age less than $12$ years and has $20$ toys.

• A. $\frac{1}{10}$
• B. $\frac{1}{20}$
• C. $\frac{19}{200}$
• D. $\frac{37}{200}$

Answer 1

The correct option is D $\frac{37}{200}$

Total no. of childrens $=3+8+20+15+6+12+18+11+22+17+15+10+13+10+10+10=200$

$P\left(N\right)=\frac{\text{No. of childrens having age less than 12 and 20 toys}}{\text{Total no. of childrens}}$

$=\frac{8+12+17}{200}=\frac{37}{200}$