Question

that the child is $12$ years old and has more than $20$ toys.

• A. $\frac{1}{5}$
• B. $\frac{1}{20}$
• C. $\frac{1}{10}$
• D. $\frac{1}{200}$

Answer 1

The correct option is C $\frac{1}{10}$

Total no. of childrens $=3+8+20+15+6+12+18+11+22+17+15+10+13+10+10+10=200$

$P\left(D\right)=\frac{\text{No. of children having age of 12 and having moe that 20 toys}}{\text{Total no. of childrens}}$

$=\frac{10+10}{200}=\frac{20}{200}=\frac{1}{10}$