The 10th term of A.P. 2, 7, 12,............ is:

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Solution

The correct option is C 47
Given 'a' = 2, 'd' = 5, 'n' = 10. Find the 10th term.
$t_{10} = a + (n - 1) d ⟹ t_{10} = 2 + (10 - 1) 5 ⟹ t_{10} = 2 + 45 = 47$ .
The 10th term of the sequence is 47.

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