The 20th term from the end of the AP 3, 8, 13, ..., 253 is
(a) 163
(b) 158
(c) 153
(d) 148
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Solution
(b) 158
Here, a = 3, d = (8 - 3) = 5, l = 253 and n = 20th
Now, nth term from the end = [l - (n - 1)d]
20th term from the end = [253 - (20 - 1) ⨯ 5]
= [253 - (19 ⨯ 5)] = (253 - 95) = 158
Hence, the 20th term from the end of the AP is 158.