The 7th term of an AP is -4 and its 13th term is - 16. Find the AP.
The nth term of an AP is given by a+(n-1)d.
As per the question, a+6d=−4a+12d=−16
Subtracting we get, 6d=−12⇒d=−2
Now, a+6×(−2)=−4⇒a=8
So, the AP is 8, 6, 4, 2, 0, -2, -4 .....