The absolute maximum of $y = x^{2} - 3 x + 2$ is

4

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6

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2

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0

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Solution

The correct option is D $2$
Now,
$\begin{matrix} f (x) = x^{3} - 3 x + 2 x^{3} - 3 x + 2 = 0 x^{3} - 2 x - x + 2 = 0 x (x - 2) - 1 (x - 2) = 0 (x - 1) (x - 2) = 0 x = 1, 2 \end{matrix}$

Hence,
Option $C$ is correct answer.

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