The actual number of atoms present in 12 g of 126C is -

The correct option is A 6.022×10^23 12 g #160;of C means one mole of C and 1 mole of carbon represent number of atoms = #160;Avogadro's #160 ...

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Byju's Answer

Standard X

Chemistry

Mole Concept and Avogadro's Number

The actual nu...

Question

The actual number of atoms present in $12$ g of $_{6}^{12} C$ is ______.

1.084 \times 10^{25}

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6.022 \times 10^{23}

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6.022 \times 10^{22}

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Solution

The correct option is A $6.022 \times 10^{23}$
$12$ g of C means one mole of C and 1 mole of carbon represent number of atoms = Avogadro's number . That is $6.023 \times 10^{23}$

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Similar questions

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

Question 9
3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are
(a) $6.68 \times 10^{23}$
(b) $6.09 \times 10^{22}$
(c) $6.022 \times 10^{23}$
(d) $6.022 \times 10^{21}$

How many moles of molecules and atoms of sulphur are present in 0.1 mole of S₈?

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

The number of electrons present in 60 g water is

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The actual number of atoms present in 12 g of 126C is ______.

The correct option is A 6.022×102312 g of C means one mole of C and 1 mole of carbon represent number of atoms = Avogadro's number . That is 6.023×1023

The actual number of atoms present in $12$ g of $_{6}^{12} C$ is ______.

The correct option is A $6.022 \times 10^{23}$
$12$ g of C means one mole of C and 1 mole of carbon represent number of atoms = Avogadro's number . That is $6.023 \times 10^{23}$