You visited us 1 times! Enjoying our articles? Unlock Full Access!

Satellites

The additiona...

Question

The additional kinetic energy to be provided to a satellite of mass m revolving around a planet of mass $M$ , to transfer it from a circular orbit of radius $R_{1}$ to another of radius $R_{2} (R_{2} > R_{1})$ is

G m M (\frac{1}{R_{1}^{2}} - \frac{1}{R_{2}^{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

G m M (\frac{1}{R_{1}} - \frac{1}{R_{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 G m M (\frac{1}{R_{1}} - \frac{1}{R_{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

GmM

(\frac{1}{R_{1}} - \frac{1}{R_{2}})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $\frac{1}{2}$ GmM $(\frac{1}{R_{1}} - \frac{1}{R_{2}})$
We know that,
KE = $(- \frac{G M m}{2 R_{2}}) - (\frac{G M m}{2 R_{1}})$
KE = $\frac{G M m}{2} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Suggest Corrections

Similar questions

m

M

R_{1}

R_{2} (R_{2} > R_{1})

R_{1}

R_{2} (R_{2} > R_{1})

R_{1}

R_{2}

R_{1} + R_{2} = R

R_{1}^{2} + R_{2}^{2} = R^{2}

R_{1} + R_{2} < R

R_{1}^{2} + R_{2}^{2} < R_{2}

R_{1}

R_{2}

\frac{n}{1}

m

M

2 R

3 R

Join BYJU'S Learning Program