The admittance parameter $y_{12}$ in the 2-port network in Figure is

-0.2 mho

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0.1 mho

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-0.05 mho

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0.05 mho

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Solution

The correct option is C -0.05 mho
$[\begin{matrix} y_{1} + y_{3} & - y_{3} - y_{3} & y_{2} + y_{3} \end{matrix}] = [\begin{matrix} y_{11} & y_{12} y_{21} & y_{22} \end{matrix}]$

$y_{12} = - y_{3}$

$y_{12} = - \frac{1}{20} = - 0.05 m h o$

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Similar questions

I_{1} = Y_{11} E_{1} + Y_{12} E_{2}

I_{2} = Y_{21} E_{1} + Y_{22} E_{2}

Y_{11} Y_{12}, Y_{21} a n d Y_{22}

h_{21}

Y_{22}

In the h-parameter model of the 2-port network given in the figure shown, the value of $h_{22}$ (in S) is

Z_{11}

Z_{21}

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