The age of father 10 years ago was thrice the age of his son. 10 years hence, father's age will be twice that of his son. The ratio of their present ages is :

5 : 2

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7 : 3

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9 : 2

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13 : 4

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Solution

The correct option is B $7 : 3$
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, $(3 x + 10) + 10 = 2 [(x + 10) + 10]$
$3 x + 20 = 2 x + 40$
$x = 20$
Required ratio = $(3 x + 10) : (x + 10) = 70 : 30 = 7 : 3$

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The age of father 10 years ago was thrice the age of his son. 10 years hence, father's age will be twice that of his son. The ratio of their present ages is :

The correct option is B 7:3Let the ages of father and son 10 years ago be 3x and x years respectively.Then, (3x+10)+10=2[(x+10)+10]3x+20=2x+40x=20Required ratio = (3x+10):(x+10)=70:30=7:3

The correct option is B $7 : 3$
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, $(3 x + 10) + 10 = 2 [(x + 10) + 10]$
$3 x + 20 = 2 x + 40$
$x = 20$
Required ratio = $(3 x + 10) : (x + 10) = 70 : 30 = 7 : 3$