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Question

The ages of two friends Ani and Biju differ by 3year.

Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy.

The ages of Cathy and Dharam differ by 30year.

Find the ages of Ani and Biju.


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Solution

Let the present age of Ani =ayears

Let the present age of Biju =byears

Given that the age of Ani and Biju differ by 3 years

Step 1 - When Ani is older than Biju

a-b=3-----(i)

Also,

Ani's father Dharam is twice as old as Ani

The present age of Dharam =2a

And, Biju is twice as old as Cathy

The present age of Biju =2×Present age of Cathy

Present age of Cathy =presentageofBiju2

Present age of Cathy =b2

Also, The age of Dharam and Cathy differ by 30years

2a-b2=30------(ii)

From equation(i) a=b+3substituting the value in equation(ii)

2b+3-b2=304b+3-b2=304b+12-b=603b+12=603b=60-123b=48b=483b=16years

a=b+3a=16+3a=19years

Hence, the age of Biju is 16 years

the age of Ani is 19 years

Step-2-When Biju is older than Ani

b-a=3b=a+3---------(iii)

substituting the value of b from eq(iii) in eq(ii)

2a-a+32=304a-(a+3)2=304a-a-32=303a-32=303a-3=603a=63a=633a=21years

b=3+ab=21+3b=24years

Hence, The age of Ani is 21 yrs

The age of Biju is 24yrs.


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