Question

The ages of two persons are in ratio 5:7.Eighteen years ago their ages were in the ratio 8:13.Find their present age ?

Answer 1

Let the present ages of two persons be 5x and 7x years
Age of two persons 18 years ago are (5x – 18) and (7x – 18) years
Given (5x – 18)/(7x – 18) = 8/13
13(5x – 18) = 8(7x – 18)
65x – 234 = 56x – 144
9x = 90
Therefore, x = 10
Thus age of the two persons are 50 and 70 years