Question

The amount (in g) of H2SO4 present in 250 ml of 1M solution is Solve using law of equivalence .

Answer 1

Molarity

• The molarity of a given solution is defined as the total number of moles of solute per liter of solution

• It is given by the equation:

  $M=\frac{n}{V}where,n=no.ofmoles$

  $V=volumeinlitres$

• The number of moles can be calculated as $\frac{Givenweight}{Molecularweight}=\frac{W}{M}$.

Law of Equivalence

• According to the law of equivalence, the number of gram equivalents of each reactant and product in a reaction are equal.​

Given that V=250 mL=$\frac{250}{1000}L$ , Molarity=1 M, we know that the molecular weight of $H_{2}S{O}_4$ is 98 gm.

So, lets calculate the amount of $H_{2}S{O}_4$ present in 250 ml of 1M solution.

$Molarity=\frac{n}{V}$

$=\frac{W}{M\times V}$

$W=Molarity\times M\times V$

$=1\times 98\times \frac{250}{1000}$

$=24.5gm$