The amount of $H_{2} O_{2}$ present in $1 L$ of $1.5 N H_{2} O_{2}$ solution is ?

2.5

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25.5

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3.0

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8.0

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Solution

The correct option is D $25.5$ g
$N o r m a l i t y = M o l a r i t y \times n_{f}$
for $H_{2} O_{2}^{+ 1} \to H_{2} O^{- 2}$
$n_{f} = 2 \times 1 = 2$
$N = M \times 2$
$1.5 = \frac{n o . o f m o l e s}{V o l u m e} \times 2$
$1.5 = \frac{m a s s}{m o l a r m a s s o f H_{2} O_{2}} \times \frac{1}{V o l u m e} \times 2$
$1.5 = \frac{m a s s}{34} \times \frac{1}{12} \times 2$
mass of $H_{2} O_{2} = 25.5 g$

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