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Standard X

Physics

Power

The amount of...

Question

The amount of heat energy required to convert $1 k g$ of ice at $- 10^{o} C$ to water at $100^{o} C$ is $7, 77, 000 J$ . Calculate the specific latent heat of ice. Specific heat capacity of ice $= 2100 J k g^{- 1} K^{- 1}$ , specific heat capacity of water $= 4200 J k g^{- 1} K^{- 1}$

1, 68, 000 J k g^{- 1}

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6, 36, 000 J k g^{- 1}

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6, 72, 000 J k g^{- 1}

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3, 36, 000 J k g^{- 1}

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Solution

The correct option is D $3, 36, 000 J k g^{- 1}$
Energy required to increase the ice to 0 $^{o} C$ ,then gain latent heat to convert into water and then to raise its temperature to 100 $^{o} C$
Energy required $= 777000 = 1 \times 2100 \times 10 + 1 \times L + 1 \times 4200 \times 100$
L=latent heat of ice $33600 J K g^{- 1}$

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Similar questions

$Calculate the amount of heat required to convert 1.00 kg of ice at -10°C$
$at normal pressure to steam at 100°C.$

$The specific heat capacity of ice = 2100 J k g^{- 1} K^{- 1}$

$Latent heat of fusion of ice = 3.36 \times 10^{5} J k g^{- 1}$

$The specific heat capacity of water = 4200 J k g^{- 1} K^{- 1}$

$Latent heat of vaporization of water = 2.25 \times 10^{6} J k g - 1$

Q. A refrigerator converts

100 g

of water at

20^{o} C

to ice at -

10^{o} C

73.5 m i n

. Calculate the average rate of heat extraction in Watt. The specific heat capacity of water is

4.2 J g^{- 1} K^{- 1}

, specific latent heat of ice is

336 J g^{- 1}

and the specific heat capacity of ice is

2.1 J g^{- 1} K^{- 1}

Q. Find the result of mixing

10 g

of ice at

- 10^{o} C

with

10 g

of water at

10^{o} C

. Specific heat capacity of ice

= 2.1 J g^{- 1} K^{- 1}

, specific latent heat of ice

= 336 J g^{- 1}

and specific heat capacity of water

= 4.2 J g^{- 1} K^{- 1}

10 g of ice at $0^{o} C$ absorbs 5460 J of heat energy to melt and change to water at $50^{o} C$ . Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J $k g^{-} 1 K^{- 1}$ .

250 g

of water at

30^{o} C

is contained in a copper vessel of mass

50 g

. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to

5^{o} C

. Given : specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

, specific heat capacity of copper

= 400 J k g^{- 1} K^{- 1}

, specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

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The amount of heat energy required to convert 1 kg of ice at −10oC to water at 100oC is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice =2100Jkg−1K−1, specific heat capacity of water =4200 Jkg−1K−1

The correct option is D 3,36,000Jkg−1Energy required to increase the ice to 0oC ,then gain latent heat to convert into water and then to raise its temperature to 100oCEnergy required=777000=1×2100×10+1×L+1×4200×100 L=latent heat of ice 33600 JKg−1

The amount of heat energy required to convert $1 k g$ of ice at $- 10^{o} C$ to water at $100^{o} C$ is $7, 77, 000 J$ . Calculate the specific latent heat of ice. Specific heat capacity of ice $= 2100 J k g^{- 1} K^{- 1}$ , specific heat capacity of water $= 4200 J k g^{- 1} K^{- 1}$