The amount of oxygen in $3.6$ moles of water is:

115.2 gm

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57.6 gm

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28.8 gm

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18.4 gm

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Solution

The correct option is A 57.6 gm
1 mole of $H_{2} O$ contains $1$ mole of oxygen = 16gm of oxygen atom

Moles of oxygen $= \frac{W e i g h t}{M o l e c u l a r w e i g h t o f o x y g e n}$

$∴ 3.6 = \frac{W e i g h t}{16}$

Weight of oxygen $= 57.6$ g.

Hence, option B is correct.

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