The amplification factor of a triode is $50$ . If the grid potential is decreased by $0.20 V$ . What increase, in plate potential will keep the plate current unchanged?

5 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.2 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $10 V$
Amplification factor of a triode, $μ = \frac{Δ V_{p}}{Δ V_{g}}$
$\Rightarrow Δ V_{p} = - μ \times Δ V_{s} = - 50 (- 20) = 10 V$

Suggest Corrections

Similar questions

Q. A triode valve has an amplification factor of

20

and its plate is given a potential of

300 V

. The grid voltage to reduce the plate current to zero, is

A triode valve operates at $V_{p} = 225 V$ and $V_{R}$ = -0.5 V.
The plate current remains unchanged if the plate voltage is increased to 250 V and the grid voltage is decreased to - 2.5 V calculate the amplifiation factor.

Q. The amplification factor of a triode operating in the linear region depends strongly on
(a) the temperature of the cathode
(b) the plate potential
(c) the grid potential
(d) the separations of the grid from the cathode and the anode

Q. The plate resistance and amplification factor of a triode are 10kΩ and 20. The tube is operated at plate voltage 250 V and grid voltage −7.5 V. The plate current is 10 mA. (a) To what value should the grid voltage be changed so as to increase the plate current to 15 mA? (b) To what value should the plate voltage be changed to take the plate current back to 10 mA?

Q. The plate resistance of a triode is 8 kΩ and the transconductance is 2.5 millimho. (a) If the plate voltage is increased by 48 V and the grid voltage is kept constant, what will be the increase in the plate current? (b) With plate voltage kept constant at this increased value, by how much should the grid voltage be decreased in order to bring the plate current back to its initial value?

Join BYJU'S Learning Program

The amplification factor of a triode is 50. If the grid potential is decreased by 0.20V. What increase, in plate potential will keep the plate current unchanged?

The correct option is B 10VAmplification factor of a triode, μ=ΔVpΔVg⇒ΔVp=−μ×ΔVs=−50(−20)=10V

The amplification factor of a triode is $50$ . If the grid potential is decreased by $0.20 V$ . What increase, in plate potential will keep the plate current unchanged?

The correct option is B $10 V$
Amplification factor of a triode, $μ = \frac{Δ V_{p}}{Δ V_{g}}$
$\Rightarrow Δ V_{p} = - μ \times Δ V_{s} = - 50 (- 20) = 10 V$