The amplitude and the periodic time of a S.H.M. are 5cm and 6sec respectively. At a distance of 2.5 cm away from the mean position, the phase will be

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Solution

The correct option is D

Equation of motion is $y = 5 s i n \frac{2 π t}{6}$ . For $y = 2.5 c m$

$2.5 = 5 s i n \frac{2 π t}{6} \Rightarrow \frac{2 π t}{6} = \frac{π}{6} \Rightarrow t = \frac{1}{2} s e c$

And phase $= \frac{2 π t}{6} = \frac{π}{6}$

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The amplitude and the periodic time of a S.H.M. are 5cm and 6sec respectively. At a distance of 2.5 cm away from the mean position, the phase will be

The correct option is D Equation of motion is y=5sin 2πt6. For y=2.5 cm 2.5=5sin 2πt6⇒2πt6=π6⇒t=12 sec And phase =2πt6=π6

The correct option is D

Equation of motion is $y = 5 s i n \frac{2 π t}{6}$ . For $y = 2.5 c m$

$2.5 = 5 s i n \frac{2 π t}{6} \Rightarrow \frac{2 π t}{6} = \frac{π}{6} \Rightarrow t = \frac{1}{2} s e c$

And phase $= \frac{2 π t}{6} = \frac{π}{6}$