Question

The angle between the line passing through the points $(3,1,-2)$ and $(4,0,-4)$ and the line passing through the points $(4,-3,3)$ and $(6,-2,2)$ is :

Answer 1

$\begin{array}{c}Linepas\sin gthrough\left(3,1,-2\right)and\left(4,0,-4\right)isparallelto\left(1,-1,-2\right)\\ linepas\sin gthrough\left(4,-3,3\right)and\left(6,-1,2\right)isparallelto\left(-2,-1,1\right)\\ \cos \theta =\frac{\left|-2+1-2\right|}{\sqrt{6}\sqrt{6}}=\frac{3}{9}=\frac{1}{2}\\ \theta ={60}^{\circ }\end{array}$