The equation of the line passing through the points $(4, - 2)$ and $(- 3, 3)$ is

7 y - 5 x + 34 = 0

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7 y + 5 x - 34 = 0

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7 y - 5 x + 6 = 0

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7 y + 5 x - 6 = 0

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Solution

The correct option is D $7 y + 5 x - 6 = 0$
Given, the line is passing through the points $(4, - 2)$ and $(- 3, 3)$
So, we have slope of the line as $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{3 - (- 2)}{- 3 - 4} = \frac{- 5}{7}$
Thus, the equation of the line is given as
$y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (- 2) = \frac{- 5}{7} (x - 4)$
$\Rightarrow 7 (y + 2) = - 5 (x - 4)$
$\Rightarrow 7 y + 5 x - 6 = 0$

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The equation of the line passing through the points (4,−2) and (−3,3) is

The equation of the line passing through the points $(4, - 2)$ and $(- 3, 3)$ is