AD bisects BC in the ratio 2:3.
Therefore, area of △ABD : area of △ADC = 2 : 3
Given, area of △ABD = 20 cm2
Therefore area of △ADC = 30 cm2.
The angle bisector of ∠A divides the side BC of △ABC in the ratio 2 :3. The area of △ABD = 20 cm2. Area of △ ADC =
A point D is taken on the side of BC of ∆ABC such that BD = 2DC. Then
In the figure given, D divides the side BC of △ABC in the ratio 3:5. What is the area of △ABD in terms of area of △ABC?