Question

The angle of a wedge shaped block is being checked using a 200 mm sine bar with gauge blocks of 26.62 mm height under one end of sine bar. The dial gauge readings at each end of the work piece vary by 0.02 mm, the gauge block end being low. If the work piece is 40 mm long, the next height of gauge block tried is

• A. 26.72 mm
• B. 26.64 mm
• C. 26.60 mm
• D. 26.52 mm

Answer 1

The correct option is A 26.72 mm

$40\to 0.02$

$200\to \frac{0.02}{40}\times 200=0.1$

$h^{\prime }=h+0.1$

= 26.62 +0.1 =26.72 mm