The angle of projection at which the horizontal range and maximum height of projectile are equal is
45∘
θ=tan−1(0.25)
θ=tan−14 or (θ=76∘)
60∘
R = 4H cot θ When R = H then cot θ=14⇒θ=tan−1(4)
The angle of projection, for which the horizontal range and the maximum height of a projectile are equal is