The angles of a pentagon are x-x-10-x-20-2 x-44- and 2 x-70- then x-

The correct option is A Sum of interior angles of a pentagon =(5 2)× 180^∘ x+x 10+x+20+2x 44+2x 70=3(180^∘) 7x 104 =540^∘ 7x = 644 x = 92° ...

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Byju's Answer

Standard VIII

Mathematics

Sum of Angles of a Polygon

The angles of...

Question

The angles of a pentagon are $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x=___

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Solution

The correct option is A

Sum of interior angles of a pentagon $= (5 - 2) \times 180^{\circ}$

$x + x - 10 + x + 20 + 2 x - 44 + 2 x - 70 = 3 (180^{\circ})$

$7 x - 104 = 540^{\circ}$

$7 x = 644$

$x = 92 °$

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Similar questions

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If the interior angles of a pentagen measure $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x = ___ .

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The angles of a pentagon are x∘,(x−10)∘,(x+20)∘,(2x−44)∘ and (2x−70)∘, then x=___

The correct option is A Sum of interior angles of a pentagon =(5−2)×180∘ x+x−10+x+20+2x−44+2x−70=3(180∘) 7x−104=540∘ 7x=644 x=92°

The angles of a pentagon are $x^{\circ}, (x - 10)^{\circ}, (x + 20)^{\circ}, (2 x - 44)^{\circ}$ and $(2 x - 70)^{\circ}$ , then x=___

The correct option is A

Sum of interior angles of a pentagon $= (5 - 2) \times 180^{\circ}$

$x + x - 10 + x + 20 + 2 x - 44 + 2 x - 70 = 3 (180^{\circ})$

$7 x - 104 = 540^{\circ}$

$7 x = 644$

$x = 92 °$