Question

The angular momentum of $3p$-orbitals in terms of $h^{\ast }(h^{\ast }=\frac{h}{2\pi })$ is:

• A. $\sqrt{2}{h}^{\ast }$
• B. $2h^{\ast }$
• C. $\frac{h^{\ast }}{\sqrt{2}}$
• D. $h^{\ast }$

Answer 1

The correct option is A $\sqrt{2}{h}^{\ast }$

As we know,
Angular momentum in an orbital $=\sqrt{l(l+1)}\cdot \frac{h}{2\pi }$

$l=1$ for 3p orbital,

Angular momentum in 3p is

$=\sqrt{1(1+1)}\cdot \frac{h}{2\pi }=\sqrt{2}{h}^{\ast }$